All 20 questions from the Post-UTME Screening (Post-UTME) Chemistry 2016 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.
During the electrolysis of acidified water, how many Faraday(s) will liberate 5.6dm3 of oxygen gas, measured at s.t.p? [Molar volume of a gas at s.t.p = 22.4 dm3]
A. 0.50 F
B. 1.00 FCorrect
C. 1.50 F
D. 2.00 F
Explanation
Moles O2 = 5.6/22.4 = 0.25mol. Since 4 electrons (Faradays) are needed per mole of O2 (2H2O -> O2 + 4H+ + 4e-), Faradays = 0.25 x 4 = 1.00F.
In an electrolytic process, a metal X is deposited according to the equation X2+ + 2e(aq) -> X. Calculate the quantity of electricity required to deposit 0.5 mole of X. [F = 96,500 C mol-1]
Cu2+(aq) [pale blue] + 4NH3(aq) <=> [Cu(NH3)4]2+(aq) [Deep blue solution]. In the equation above, addition of a few drops of dilute hydrochloric acid will produce
A. an increase in the deepness of the solution
B. a stable chemical system
C. a decrease in the deepness of the solutionCorrect
D. a decrease in the concentration of Cu2+
Explanation
HCl reacts with (protonates) free NH3, reducing its concentration and shifting equilibrium back towards pale blue Cu2+, decreasing the deep blue colour.
A galvanic cell makes use of the following half reactions: Li(s) -> Li+(aq) + e, E = +3.05V; F2(g) + 2e(aq) -> 2F-(aq), E = +2.85V. What is the voltage of the cell?
A. 0.20V
B. 3.25V
C. 5.90VCorrect
D. 8.95V
Explanation
Cell voltage = sum of the given oxidation potential (Li) and reduction potential (F2): 3.05 + 2.85 = 5.90V.
Trioxonitrate (V) acid prepared in the laboratory has a yellow colour due to the presence of dissolved
A. N2O
B. NO2Correct
C. NO
D. NO3
Explanation
Dissolved NO2 (formed from partial decomposition of the acid) gives laboratory-prepared concentrated trioxonitrate(V) acid its characteristic yellow tinge.
The formation of a dense white precipitate, on addition of dilute hydrochloric acid and barium chloride solution to an unknown solution on warming indicates the presence of
A. Cl -
B. SO3 2-
C. NO3 -
D. SO4 2-Correct
Explanation
Barium sulphate (BaSO4) is an insoluble white precipitate that remains even in the presence of dilute HCl, indicating the presence of sulphate ions.