Post-UTME Chemistry 2016 Objective — Question 7
Question 7 of 20 from the Post-UTME Screening (Post-UTME) Chemistry 2016 Objective paper, with the correct answer and a full explanation.
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A galvanic cell makes use of the following half reactions: Li(s) -> Li+(aq) + e, E = +3.05V; F2(g) + 2e(aq) -> 2F-(aq), E = +2.85V. What is the voltage of the cell?
- A. 0.20V
- B. 3.25V
- C. 5.90VCorrect
- D. 8.95V
Explanation
Cell voltage = sum of the given oxidation potential (Li) and reduction potential (F2): 3.05 + 2.85 = 5.90V.
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