Post-UTME Chemistry 2017 Objective — Question 5
Question 5 of 20 from the Post-UTME Screening (Post-UTME) Chemistry 2017 Objective paper, with the correct answer and a full explanation.
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2HI + H2O2 -> 2H2O + I2. In the equation above, the oxidation number of I has changed from
- A. +1 to 0
- B. 0 to +1
- C. -1 to 0Correct
- D. 0 to -1
Explanation
Iodine in HI has oxidation number -1; in I2 it is 0. The oxidation number changes from -1 to 0.
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