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Post-UTME Chemistry 2017 Objective Past Questions

All 20 questions from the Post-UTME Screening (Post-UTME) Chemistry 2017 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Chemistry 2017 Objective — Question 1

What is quantity of iron is deposited when a current of 5A is passed through a solution containing Fe3+ ions for 19.3 minutes? [Fe=56, F=96,500C mol-1]

  • A. 0.56g
  • B. 1.12gCorrect
  • C. 2.24g
  • D. 3.36g

Explanation

Q=It=5x(19.3x60)=5790C. Fe3+ + 3e -> Fe, so moles=Q/(3F)=5790/(3x96500)=0.02mol. Mass=0.02x56=1.12g.

Chemistry 2017 Objective — Question 2

Cu2+(aq) + 2e -> Cu(s), E = +0.34V; Zn2+(aq) + 2e -> Zn(s), E = -0.76V. From the equations above, it can be concluded that

  • A. Cu can easily reduce Zn
  • B. Zn can easily oxidize Cu
  • C. Cu can easily oxidize Zn
  • D. Zn can easily reduce any metalCorrect

Explanation

Zinc, being more reactive (more negative electrode potential) than most common metals, readily acts as a reducing agent towards other metal ions.

Chemistry 2017 Objective — Question 3

During the electrolysis of dilute sodium chloride solution, the product at the anode is

  • A. sodium
  • B. hydrogen
  • C. oxygenCorrect
  • D. chlorine

Explanation

In dilute NaCl solution, hydroxide ions are preferentially discharged at the anode, producing oxygen gas.

Chemistry 2017 Objective — Question 4

Palmwine exposed to the atmosphere for sometime becomes sour due to

  • A. oxidationCorrect
  • B. reduction
  • C. hydrolysis
  • D. hydration

Explanation

Exposure to air allows bacteria to oxidise the ethanol in palmwine to ethanoic (acetic) acid, making it sour.

Chemistry 2017 Objective — Question 5

2HI + H2O2 -> 2H2O + I2. In the equation above, the oxidation number of I has changed from

  • A. +1 to 0
  • B. 0 to +1
  • C. -1 to 0Correct
  • D. 0 to -1

Explanation

Iodine in HI has oxidation number -1; in I2 it is 0. The oxidation number changes from -1 to 0.

Chemistry 2017 Objective — Question 6

A chemical substance reaction attains equilibrium when

  • A. delta H < 0
  • B. delta G < 0
  • C. delta G = 0Correct
  • D. delta H = 0

Explanation

Chemical equilibrium is characterised by the Gibbs free energy change (delta G) being zero.

Chemistry 2017 Objective — Question 7

Substance / delta H kJ mol-1: CH4 -74.8, O2 0, C -393.5, H2O -286. Using the table above, calculate the delta H for the following reaction at 25C: CH4(g) + 2O2(g) -> CO2(g) + 2H2O(g).

  • A. -890.7kJCorrect
  • B. -819.0kJ
  • C. +819.0kJ
  • D. +890.7kJ

Explanation

delta H = [(-393.5)+2(-286)] - [(-74.8)+2(0)] = -965.5 - (-74.8) = -890.7 kJ.

Chemistry 2017 Objective — Question 8

N2(g) + O2(g) <=> 2NO(g), delta H + 92kJ. The equilibrium represented by the above equation can be shifted to right by

  • A. decreasing the temperature
  • B. using a catalyst
  • C. increasing the pressure
  • D. using excess nitrogenCorrect

Explanation

Adding excess N2 (a reactant) shifts the equilibrium to the right (Le Chatelier's principle); the reaction is endothermic, so cooling would not help, and pressure has no effect since moles of gas are equal on both sides.

Chemistry 2017 Objective — Question 9

N2O4(g) <=> 2NO2(g). A high yield of nitrogen (IV) oxide can be obtained the reaction above by

  • A. increasing the temperatureCorrect
  • B. lowering the temperature
  • C. increasing the pressure
  • D. lowering the pressure

Explanation

The dissociation of N2O4 to NO2 is endothermic, so raising the temperature shifts equilibrium towards greater NO2 (nitrogen(IV) oxide) yield.

Chemistry 2017 Objective — Question 10

CuSO4(aq) + H2S(g) -> CuS(s) + H2SO4(aq). In the reaction above, hydrogen sulphide acts as

  • A. a weak acid
  • B. a reducing agent
  • C. an oxidizing agent
  • D. a precipitating agentCorrect

Explanation

H2S provides sulphide ions that precipitate copper as insoluble CuS, acting as a precipitating agent.

Chemistry 2017 Objective — Question 11

The cleansing action of soap in hard water is not satisfactory because soap

  • A. is a salt of fatty acids
  • B. is not a detergent
  • C. forms insoluble saltsCorrect
  • D. forms soluble salt

Explanation

In hard water, soap reacts with calcium and magnesium ions to form insoluble scum (salts), reducing its cleansing effectiveness.

Chemistry 2017 Objective — Question 12

If the solubility of KHCO3 is 0.40 mol/dm3 at room temperature, calculate the mass of KHCO3 in 100cm3 of the solution at that temperature.

  • A. 100.0g
  • B. 40.0g
  • C. 10.0g
  • D. 4.0gCorrect

Explanation

Moles = 0.40 x 0.100 = 0.040mol. Molar mass KHCO3 = 100g/mol. Mass = 0.040 x 100 = 4.0g.

Chemistry 2017 Objective — Question 13

An acid salt can be produced using

  • A. tetraoxsulphate (VI) acidCorrect
  • B. ethanoic acid
  • C. trioxonitrate (V) acid
  • D. hydrochloric acid

Explanation

Acid salts form from polybasic (e.g. dibasic) acids like tetraoxosulphate(VI) acid, which can be only partially neutralised.

Chemistry 2017 Objective — Question 14

Which of the following is deliquescent?

  • A. CuSO4
  • B. NaOHCorrect
  • C. CuCl2
  • D. Na2SO4

Explanation

Sodium hydroxide (NaOH) is a classic deliquescent substance, absorbing moisture from the air until it dissolves.

Chemistry 2017 Objective — Question 15

One of the products formed when chlorine is bubbled slowly through a solution of potassium iodide is

  • A. potassium
  • B. solid iodineCorrect
  • C. potassium hydroxide solution
  • D. hydrogen iodide vapour

Explanation

Chlorine displaces iodine from potassium iodide (Cl2 + 2KI -> 2KCl + I2), producing iodine, which appears as a solid/dark precipitate.

Chemistry 2017 Objective — Question 16

Which of the following is produced by each of NaNO3, Pb(NO3)2 and AgNO3 when decomposed by heat?

  • A. OxygenCorrect
  • B. Nitrogen (IV) oxide
  • C. Nitrogen (II) oxide
  • D. Nitrogen

Explanation

All nitrates release oxygen gas as a common product upon thermal decomposition, alongside other products depending on the metal.

Chemistry 2017 Objective — Question 17

In the extraction of iron, limestone is fed into the furnace to provide

  • A. carbon (IV) oxide which reacts with hot coke
  • B. carbon (II) oxide which reduces iron (III) oxide
  • C. both carbon (IV) and carbon (II) oxides for reduction processes in the furnace
  • D. calcium oxide which reacts with silicon (IV) oxideCorrect

Explanation

Limestone decomposes in the furnace to form calcium oxide, which reacts with silica impurities to form slag, removing them from the molten iron.

Chemistry 2017 Objective — Question 18

Electrolytic method is usually employed in the extraction of

  • A. aluminumCorrect
  • B. copper
  • C. zinc
  • D. iron

Explanation

Aluminium, being highly reactive, is extracted by electrolysis of its molten oxide (in cryolite).

Chemistry 2017 Objective — Question 19

The compound of sodium used in the manufacture of glass is

  • A. Na2SO4 10H2O
  • B. NaHCO3
  • C. Na2CO3 10H2OCorrect
  • D. NaOh

Explanation

Sodium carbonate (washing soda, Na2CO3.10H2O) is used as a raw material in glass manufacture.

Chemistry 2017 Objective — Question 20

Which of the following is typical of transition metals?

  • A. They form colourless complexes
  • B. They exhibit variable valencesCorrect
  • C. They have low melting points
  • D. They do not act as catalysts

Explanation

Transition metals characteristically exhibit variable (multiple) oxidation states/valences.

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