Post-UTME Chemistry 2017 Objective — Question 7
Question 7 of 20 from the Post-UTME Screening (Post-UTME) Chemistry 2017 Objective paper, with the correct answer and a full explanation.
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Substance / delta H kJ mol-1: CH4 -74.8, O2 0, C -393.5, H2O -286. Using the table above, calculate the delta H for the following reaction at 25C: CH4(g) + 2O2(g) -> CO2(g) + 2H2O(g).
- A. -890.7kJCorrect
- B. -819.0kJ
- C. +819.0kJ
- D. +890.7kJ
Explanation
delta H = [(-393.5)+2(-286)] - [(-74.8)+2(0)] = -965.5 - (-74.8) = -890.7 kJ.
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