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Post-UTME Chemistry 2018 Objective Past Questions

All 21 questions from the Post-UTME Screening (Post-UTME) Chemistry 2018 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Chemistry 2018 Objective — Question 1

H2S + Cl2 -> 2HCl + S. In the reaction above, the oxidation number of chlorine changed from

  • A. 0 to -1Correct
  • B. -1 to 0
  • C. -2 to 0
  • D. 0 to 2

Explanation

Chlorine in Cl2 has oxidation number 0; in HCl it is -1. The oxidation number changes from 0 to -1.

Chemistry 2018 Objective — Question 2

2K2Cr2O7(s) + 2H2O(l) + 3S(s) -> 3SO2(g) + 4KOH(aq) + 2Cr2O3. The oxidizing agent in the chemical reaction above is

  • A. K2Cr2O7Correct
  • B. S
  • C. H2O
  • D. SO2

Explanation

K2Cr2O7 (dichromate) is reduced (Cr goes from +6 to +3) in this reaction, meaning it is the oxidizing agent.

Chemistry 2018 Objective — Question 3

The criterion that a given chemical reaction can occur spontaneously is given by

  • A. delta G < 0Correct
  • B. delta G = 0
  • C. delta G >= 0
  • D. delta G > 0

Explanation

A reaction is spontaneous when the Gibbs free energy change (delta G) is negative.

Chemistry 2018 Objective — Question 4

H2O(s) -> H2O(l). The enthalpy change for the transition above is called the enthalpy of

  • A. transition
  • B. solution
  • C. sublimation
  • D. fusionCorrect

Explanation

The enthalpy change for solid converting to liquid is the enthalpy (latent heat) of fusion.

Chemistry 2018 Objective — Question 5

Which of the following processes is endothermic?

  • A. Burning of wood
  • B. Lighting a match
  • C. Dilution of concentrated H2SO4
  • D. Dissolution of ammonium chloride in waterCorrect

Explanation

Dissolving ammonium chloride in water is a classic endothermic process, absorbing heat from the surroundings.

Chemistry 2018 Objective — Question 6

2H2(g) + O2(g) -> 2H2O(g). The entropy change, delta S, for the above reaction is

  • A. positive
  • B. negativeCorrect
  • C. zero
  • D. constant

Explanation

The reaction reduces the number of gas moles from 3 to 2, decreasing disorder, so the entropy change is negative.

Chemistry 2018 Objective — Question 7

A catalyst increases the rate of a reaction by

  • A. changing the position of equilibrium
  • B. decreasing the surface area of the reactants
  • C. lowering the activation energyCorrect
  • D. increasing the activation energy

Explanation

A catalyst speeds up a reaction by providing an alternative pathway with lower activation energy.

Chemistry 2018 Objective — Question 8

Na2S2O3(aq) + 2HCl(aq) -> 2NaCl(aq) + H2O(l) + SO2(g) + S(s). The time required for a white deposit of S to appear in the action above was measured at various temperatures. These results suggest that the rate of reaction

  • A. increases for a 10C rise in temperature
  • B. decreases for a 10C rise in temperature
  • C. is unaffected by a change in temperature
  • D. doubles for a 10C rise in temperatureCorrect

Explanation

The classic thiosulphate-acid 'clock reaction' shows reaction time roughly halving (rate roughly doubling) for each 10C rise in temperature.

Chemistry 2018 Objective — Question 9

N2O4(g) <=> 2NO2(g). If the pressure in the above equilibrium is decreased, it is observed that the

  • A. gases would condense
  • B. gas mixture would become very dark brownCorrect
  • C. gas mixture would become colourless
  • D. gas would separate into two layers

Explanation

Decreasing pressure shifts the equilibrium towards the side with more gas moles (2NO2), which is a darker brown colour.

Chemistry 2018 Objective — Question 10

Which of the following oxides is amphoteric?

  • A. SO2
  • B. Na2O
  • C. CaO
  • D. Al2O3Correct

Explanation

Aluminium oxide (Al2O3) is a classic amphoteric oxide, reacting with both acids and bases.

Chemistry 2018 Objective — Question 11

In the preparation of ammonia, which of the following is used as a drying agent?

  • A. Calcium chloride
  • B. Concentrated tetraoxosulphate(VI) acid
  • C. Calcium oxideCorrect
  • D. Sodium hydroxide

Explanation

Calcium oxide (quicklime) is used to dry ammonia gas, since ammonia (a base) would react with acidic drying agents like conc. H2SO4 or form a complex with CaCl2.

Chemistry 2018 Objective — Question 12

Dilute AgNO3 is added to a solution, X, and a white precipitate soluble in excess ammonia is formed. X, therefore, contains

  • A. SO4 2-
  • B. Cl -Correct
  • C. CO3 2-
  • D. NO3 -

Explanation

AgCl forms a white precipitate that dissolves in excess ammonia (forming a soluble silver-ammine complex), indicating chloride ions are present.

Chemistry 2018 Objective — Question 13

The decomposition of potassium trioxochlorate (V) in the presence of manganese (IV) oxide is represented by

  • A. 2KClO3 -> 2KCl + 3O2Correct
  • B. KClO3 -> KClO + Mn + 2O2
  • C. 2KClO3 -> 2KMnO4 + Cl2 + O2
  • D. 2KClO3 -> 2KCl + Mn + 4O2

Explanation

MnO2 catalyses the decomposition of potassium trioxochlorate(V) (KClO3) into potassium chloride and oxygen gas: 2KClO3 -> 2KCl + 3O2.

Chemistry 2018 Objective — Question 14

When carbon (IV) oxide is bubbled into lime water, a white precipitate is first formed, which later dissolves in excess CO2 to form a colourless solution. The white precipitate and the soluble compound formed in the reactions are respectively

  • A. Na2CO3 and NaHCO3
  • B. Na2CO3 and CaCl2
  • C. Ca(OH)2 and CaCO3
  • D. CaCO3 and Ca(HCO3)2Correct

Explanation

CO2 first forms insoluble CaCO3 with limewater; with excess CO2, this converts to soluble calcium hydrogencarbonate, Ca(HCO3)2.

Chemistry 2018 Objective — Question 15

The process whereby chloride ions are removed from an aqueous solution with silver ions is known as

  • A. Filtration
  • B. Crystallization
  • C. PrecipitationCorrect
  • D. Condensation

Explanation

Silver ions react with chloride ions to form insoluble AgCl, a process known as precipitation.

Chemistry 2018 Objective — Question 16

The normal properties of some metals are modified for more practical use by

  • A. heating the pure metals
  • B. exposing them to the atmosphere
  • C. cooling them to low temperatures
  • D. alloying them with metals or non-metalsCorrect

Explanation

Alloying metals with other metals or non-metals modifies their properties (e.g. hardness, corrosion resistance) for practical applications.

Chemistry 2018 Objective — Question 17

Which of the underlisted metals can be extracted from its ores by reduction of its oxide with carbon(II) oxide?

  • A. Sodium
  • B. Calcium
  • C. IronCorrect
  • D. Magnesium

Explanation

Iron is extracted in the blast furnace by reduction of its oxide with carbon monoxide (carbon(II) oxide).

Chemistry 2018 Objective — Question 18

Which of the following metals exhibits allotropy?

  • A. Iron
  • B. TinCorrect
  • C. Zinc
  • D. Magnesium

Explanation

Tin exhibits allotropy, existing as white (beta) tin and grey (alpha) tin.

Chemistry 2018 Objective — Question 19

A salt soluble in water, gives a black precipitate with hydrogen sulphide and a deep blue colour with aqueous ammonia. The salt contains

  • A. Cu 2+Correct
  • B. Ag +
  • C. Pb 2+
  • D. Fe 2+

Explanation

Cu2+ forms a black CuS precipitate with H2S, and a characteristic deep blue complex ion with excess aqueous ammonia.

Chemistry 2018 Objective — Question 20

The IUPAC name for C(CH3)4 is

  • A. 2, 4-dimethyl-1-butane
  • B. 2, 2-dimethyl-1-propaneCorrect
  • C. -2, 2-trimethyl-1-pentane
  • D. 2, 3, 4-trimethyl propane

Explanation

C(CH3)4 (neopentane) is correctly named 2,2-dimethylpropane.

Chemistry 2018 Objective — Question 21

Using the table above (CH4 = -74.8, O2 = 0, C = -393.5, H2O = -286), calculate the delta H for the following reaction at 25C: CH4(g) + 2O2(g) -> CO2(g) + 2H2O(g).

  • A. -890.7kJCorrect
  • B. -819.0kJ
  • C. +819.0kJ
  • D. +890.7kJ

Explanation

delta H = [(-393.5)+2(-286)] - [(-74.8)+2(0)] = -965.5 - (-74.8) = -890.7 kJ.

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