Post-UTME Chemistry 2018 Objective — Question 2
Question 2 of 21 from the Post-UTME Screening (Post-UTME) Chemistry 2018 Objective paper, with the correct answer and a full explanation.
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2K2Cr2O7(s) + 2H2O(l) + 3S(s) -> 3SO2(g) + 4KOH(aq) + 2Cr2O3. The oxidizing agent in the chemical reaction above is
- A. K2Cr2O7Correct
- B. S
- C. H2O
- D. SO2
Explanation
K2Cr2O7 (dichromate) is reduced (Cr goes from +6 to +3) in this reaction, meaning it is the oxidizing agent.
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