Post-UTME Chemistry 2019 Objective — Question 1
Question 1 of 20 from the Post-UTME Screening (Post-UTME) Chemistry 2019 Objective paper, with the correct answer and a full explanation.
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If a solution contains 4.9g of tetraoxosulphate(VI) acid, calculate the amount of copper(II) oxide that will react with it. [Cu=64, O=16, S=32, H=1]
- A. 0.8g
- B. 4.0gCorrect
- C. 40.0g
- D. 80.0g
Explanation
RMM of H2SO4 = 98, RMM of CuO = 64+16 = 80. Equation: H2SO4 + CuO -> CuSO4 + H2O. 98g H2SO4 reacts with 80g CuO, so 4.9g reacts with (4.9/98) x 80 = 4.0g CuO.
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