Post-UTME Chemistry 2019 Objective — Question 2
Question 2 of 20 from the Post-UTME Screening (Post-UTME) Chemistry 2019 Objective paper, with the correct answer and a full explanation.
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A given volume of methane diffuses in 20s. How long will it take the same volume of Sulphur (IV) oxide to diffuse under the same conditions?
- A. 5s
- B. 20s
- C. 40sCorrect
- D. 60s
Explanation
Graham's law: t(SO2)/t(CH4) = sqrt(M(SO2)/M(CH4)) = sqrt(64/16) = 2. t(SO2) = 2 x 20 = 40s.
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