Post-UTME Chemistry 2019 Objective — Question 2
Question 2 of 20 from the Post-UTME Screening (Post-UTME) Chemistry 2019 Objective paper, with the correct answer and a full explanation.
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If 100cm3 of a 2.0M HNO3 solution is mixed with 150cm3 of a 1.8M KOH solution, the resulting aqueous solution is
- A. weakly acidic
- B. strongly acidic
- C. neutral
- D. strongly basicCorrect
Explanation
Moles HNO3 = 0.1x2.0=0.2mol; moles KOH=0.15x1.8=0.27mol. Excess KOH (0.07mol) remains, making the solution strongly basic.
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