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Post-UTME Mathematics 2010 Objective Past Questions

All 10 questions from the Post-UTME Screening (Post-UTME) Mathematics 2010 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Mathematics 2010 Objective — Question 1

A Headmaster contributes 7% of his income into a fund and his wife contributes 4% of her income. If the husband earns N5,500 per annum and the wife earns N4,000 per annum, find the sum of their annual contribution to the fund.

  • A. N1,045Correct
  • B. N605
  • C. N545
  • D. N490

Explanation

Husband: 7% x 5500 = 385. Wife: 4% x 4000 = 160. Sum = 385+160 = N545 (closest listed value is C; recompute confirms 545 matches option C).

Mathematics 2010 Objective — Question 2

The population of a village is 5846. Express this number to three significant figures.

  • A. 584
  • B. 585
  • C. 5840
  • D. 5850Correct

Explanation

5846 rounded to 3 significant figures is 5850 (the 4th digit, 6, rounds the 4 up to 5, giving 585 x 10 = 5850).

Mathematics 2010 Objective — Question 3

Find the equation of a line with gradient -2 passing through the point (1,2).

  • A. y=4-2xCorrect
  • B. y=4x+2
  • C. y=2x+4
  • D. y=-2x-2

Explanation

Using y-y1=m(x-x1): y-2=-2(x-1), y=2-2x+2=4-2x.

Mathematics 2010 Objective — Question 4

If v varies directly as the square of x and inversely as y, and if v=18 when x=3 and y=4, find v when x=5 and y=2.

  • A. 101
  • B. 100Correct
  • C. 98
  • D. 90

Explanation

v=kx^2/y. 18=k(9)/4, k=8. New v=8(25)/2=100.

Mathematics 2010 Objective — Question 5

Divide the expression x^3+7x^2-x^2by-1+x^2.

  • A. x^2+7x^2-7x+7
  • B. -x^3-7x+7
  • C. x-7
  • D. x+7Correct

Explanation

This item's exact polynomial expression was not fully legible in the scan; presented with reduced confidence based on the visible options.

Mathematics 2010 Objective — Question 6

The interior angles of a pentagon are 130 degrees, 118 degrees, 80 degrees, 78 degrees and x. Find the value of x.

  • A. 75 degrees
  • B. 108 degrees
  • C. 120 degrees
  • D. 134 degreesCorrect

Explanation

Sum of interior angles of a pentagon = 540 degrees. x = 540-(130+118+80+78) = 540-406 = 134 degrees.

Mathematics 2010 Objective — Question 7

A chord is 5cm from the centre of a circle of diameter 26cm. Find the length of the chord.

  • A. 35cm
  • B. 30cm
  • C. 24cmCorrect
  • D. 14cm

Explanation

Radius=13cm. Half-chord = sqrt(13^2-5^2)=sqrt(169-25)=sqrt(144)=12. Full chord = 24cm.

Mathematics 2010 Objective — Question 8

A chord XY of a circle of radius 14cm subtends an angle of 60 degrees at the centre. Find the length of arc XY.

  • A. 43/3cmCorrect
  • B. 33/3cm
  • C. 23/3cm
  • D. 13/3cm

Explanation

Arc length = (theta/360) x 2*pi*r = (60/360) x 2 x (22/7) x 14 = (1/6) x 88 = 14.67cm, closest matching listed option A (43/3 = 14.33, nearest to computed value).

Mathematics 2010 Objective — Question 9

The locus of a point which is equidistant from two given fixed points is the....

  • A. perpendicular bisector of the straight line joining themCorrect
  • B. Parallel line to the straight line joining Them
  • C. Transverse to the straight line joining them
  • D. (option not fully captured)

Explanation

The locus of points equidistant from two fixed points is the perpendicular bisector of the line segment joining them.

Mathematics 2010 Objective — Question 10

What are the integral values of x which satisfy the inequality -1<3-2x≤5?

  • A. 2, 10, -1
  • B. -1, 0, 1, 2
  • C. -1, 0, 1Correct
  • D. 0, 1, 2

Explanation

Splitting the compound inequality: 3-2x>-1 gives x<2; 3-2x≤5 gives x≥-1. So -1≤x<2, with integer values -1, 0, 1.

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