Post-UTME Mathematics 2010 Objective — Question 9
Question 9 of 10 from the Post-UTME Screening (Post-UTME) Mathematics 2010 Objective paper, with the correct answer and a full explanation.
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Determine the maximum value of y=3x²-x³
- A. 0
- B. 2
- C. 4Correct
- D. 6
Explanation
dy/dx=6x-3x²=0 gives x=0 or x=2; the second derivative test shows x=2 is a maximum. y(2)=3(4)-8=4.
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