Post-UTME Mathematics 2011 Objective — Question 7
Question 7 of 11 from the Post-UTME Screening (Post-UTME) Mathematics 2011 Objective paper, with the correct answer and a full explanation.
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The minimum value of y in the equation y = x^2-6x+8 is
- A. 8
- B. 3
- C. 0
- D. -1Correct
Explanation
Completing the square: y=(x-3)^2-1, so the minimum value is -1 (at x=3).
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