Post-UTME Mathematics 2011 Objective — Question 7
Question 7 of 9 from the Post-UTME Screening (Post-UTME) Mathematics 2011 Objective paper, with the correct answer and a full explanation.
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Find the value of (16)^(3/2) + log₁₀0.0001 + log₂32
- A. 0.065
- B. 0.650
- C. 5.500
- D. 65.00Correct
Explanation
16^1.5=64; log₁₀0.0001=-4; log₂32=5. Total = 64-4+5=65.
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