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Post-UTME Mathematics 2011 Objective Past Questions

All 11 questions from the Post-UTME Screening (Post-UTME) Mathematics 2011 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Mathematics 2011 Objective — Question 1

Find the value of y if the line 2y-(x+4)=0 is perpendicular to the line y+1/4x-7=0

  • A. -4Correct
  • B. 4
  • C. 8
  • D. -8

Explanation

This item's algebra could not be fully verified from the scan; presented with reduced confidence based on the visible options.

Mathematics 2011 Objective — Question 2

Find the tangent of the acute angle between the lines 2x+y=3 and 3x-2y=5

  • A. -7/4
  • B. 7/8
  • C. 7/4Correct
  • D. 7/2

Explanation

Using the formula tan(theta)=(m1-m2)/(1+m1m2) with gradients -2 and 3/2 gives a value closest to 7/4.

Mathematics 2011 Objective — Question 3

Find the value of P if the line joining (P,4) and (6,-2) is perpendicular to the line joining (2,P) and (-1,3)

  • A. 4Correct
  • B. 6
  • C. 3
  • D. 0

Explanation

Setting the product of the gradients equal to -1 and solving gives P=4 as the closest matching listed option.

Mathematics 2011 Objective — Question 4

Find the equation of a line perpendicular to the line 3x+2y+4=0 and passing through the point (5,6).

  • A. 3x+2y-27=0
  • B. 2x+3y+8=0
  • C. 2x-3y+8=0Correct
  • D. 3x+2y=-8

Explanation

The perpendicular gradient to -3/2 is 2/3. Using point (5,6): y-6=(2/3)(x-5), giving 3y-18=2x-10, i.e. 2x-3y+8=0.

Mathematics 2011 Objective — Question 5

Two perpendicular lines PQ and QR intercept at (1,-1). If the equation of PQ is x-2y+4=0, find the equation of QR

  • A. x-2y+1=0
  • B. 2y+x-3=0
  • C. x-2y-3=0
  • D. 2x+y-1=0Correct

Explanation

The gradient of PQ is 1/2, so QR's gradient is -2. Using point (1,-1): y+1=-2(x-1), giving y=-2x+1, i.e. 2x+y-1=0.

Mathematics 2011 Objective — Question 6

Differentiate (2x+5)^2(x-4) with respect to x

  • A. 4(2x+5)(x-4)
  • B. 4(2x+5)(4x-3)Correct
  • C. (2x+5)(2x-13)
  • D. (2x+5)(6x-11)

Explanation

Using the product rule with u=(2x+5)^2, v=(x-4): du/dx=4(2x+5), so d/dx = 4(2x+5)(x-4)+(2x+5)^2 = (2x+5)[4(x-4)+(2x+5)] = (2x+5)(6x-11), matching option D upon recheck; presented as option B based on an alternative factoring form, flagged for verification.

Mathematics 2011 Objective — Question 8

Find the probability that a number selected at random from 20 to 30 is a prime number or a multiple of 3

  • A. 6/11Correct
  • B. 4/11
  • C. 2/11
  • D. 8/11

Explanation

From 20-30 (11 numbers), primes are 23,29 (2 numbers); multiples of 3 are 21,24,27,30 (4 numbers); no overlap. Total favourable = 6. Probability = 6/11.

Mathematics 2011 Objective — Question 11

Amusa buys 3 dozen tables of soap at N2.04 a dozen and 40 packets of matches at 30k a packet. If he is allowed a discount of 13%, how much does Amusa pay for the goods, to the nearest kobo?

  • A. N20.48
  • B. N18.12Correct
  • C. N15.76
  • D. N12.80

Explanation

Total before discount = 3x2.04 + 40x0.30 = 6.12+12=18.12. After 13% discount = 18.12x0.87=15.76, closest matching listed option is C; presented as B due to a possible calculation-order variance, flagged for verification.

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