Mathematics 2011 Objective — Question 1
Calculate 3310(base5) - 1442(base5)
- A. 1313(five)Correct
- B. 2131(five)
- C. 4302(five)
- D. 1103(five)
Explanation
In decimal: 3310(5)=455, 1442(5)=247; 455-247=208, which converts back to 1313(base5).
Post-UTME Mathematics 2011 Objective Past Questions
All 9 questions from the Post-UTME Screening (Post-UTME) Mathematics 2011 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.
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Mathematics 2011 Objective — Question 2
Convert 3.1415926 to 5 decimal places
- A. 3.14160
- B. 3.14159Correct
- C. 0.31415
- D. 3.14200
Explanation
The 6th decimal digit (2) rounds down, giving 3.14159.
Mathematics 2011 Objective — Question 3
The length of a notebook 15cm was measured as 16.8cm. Calculate the percentage error to 2 significant figures
- A. 12.00%Correct
- B. 11.00%
- C. 10.71%
- D. 0.12%
Explanation
Percentage error = |16.8-15|/15 × 100 = 12%.
Mathematics 2011 Objective — Question 4
A worker's present salary is N24,000 per annum. His annual increment is 10% of his salary. What would be his annual salary at the beginning of the third year?
- A. N28,800
- B. N29,040Correct
- C. N31,200
- D. N31,944
Explanation
24000 × (1.10)² = 24000 × 1.21 = N29,040 (printed in the source with a likely digit typo).
Mathematics 2011 Objective — Question 5
Express the product of 0.0014 and 0.011 in standard form
- A. 1.54×10⁴
- B. 1.54×10⁻³
- C. 1.54×10⁻⁴
- D. 1.54×10⁻⁵Correct
Explanation
0.0014 × 0.011 = 0.0000154 = 1.54×10⁻⁵.
Mathematics 2011 Objective — Question 6
Evaluate (81)^(3/4) - (27)^(1/3) ÷ 3 × 2³ [grouped as (81^¾-27^⅓)÷(3×2³)]
- A. 27
- B. 1Correct
- C. 1/3
- D. 1
Explanation
(81^¾-27^⅓)÷(3×2³) = (27-3)/24 = 24/24 = 1.
Mathematics 2011 Objective — Question 7
Find the value of (16)^(3/2) + log₁₀0.0001 + log₂32
- A. 0.065
- B. 0.650
- C. 5.500
- D. 65.00Correct
Explanation
16^1.5=64; log₁₀0.0001=-4; log₂32=5. Total = 64-4+5=65.
Mathematics 2011 Objective — Question 8
Simplify (√12-√3)/(√12+√3)
- A. 1/3Correct
- B. 0
- C. 4
- D. 1
Explanation
√12=2√3, so (2√3-√3)/(2√3+√3) = √3/3√3 = 1/3.
Mathematics 2011 Objective — Question 9
Four members of a social first eleven cricket team are also members of the first fourteen rugby team. How many boys play for at least one of the two teams?
- A. 25
- B. 21Correct
- C. 16
- D. 3
Explanation
11+14-4 (overlap) = 21. (Question was cut off in the scanned source; reconstructed from an identical question appearing elsewhere in the series.)
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