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Post-UTME Mathematics 2016 Objective — Question 1

Question 1 of 60 from the Post-UTME Screening (Post-UTME) Mathematics 2016 Objective paper, with the correct answer and a full explanation.

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Evaluate the integral of (x + sin x) dx from 0 to pi/2.

  • A. pi^2/8 + 1Correct
  • B. pi^2/8 - 1
  • C. 1 - pi^2/8
  • D. pi^2/8

Explanation

Integral = [x^2/2 - cos(x)] from 0 to pi/2 = (pi^2/8 - cos(pi/2)) - (0 - cos(0)) = (pi^2/8 - 0) - (0-1) = pi^2/8 + 1.

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