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Post-UTME Physics 2009 Objective Past Questions

All 10 questions from the Post-UTME Screening (Post-UTME) Physics 2009 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Physics 2009 Objective — Question 1

Which of the following is a derived unit?

  • A. Meter
  • B. CoulombCorrect
  • C. Kilogram
  • D. Second

Explanation

The coulomb (charge=current×time) is derived; metre, kilogram, second, and ampere are all SI base units.

Physics 2009 Objective — Question 2

A bat emits its sound at a speed of 1650m/s (as given in the source) and receives the echoes 0.15s later. Calculate the distance of the bat from the reflector.

  • A. 8.75m
  • B. 10.50m
  • C. 87.75m
  • D. 123.75mCorrect

Explanation

Distance = speed × time / 2 = 1650 × 0.15 / 2 ≈ 123.75m.

Physics 2009 Objective — Question 3

Two identical waves travelling in the same direction are superimposed. What should be the phase difference between the waves for maximum destructive interference to occur?

  • A. 20°
  • B. 45°
  • C. 180°
  • D. 225°

Explanation

Standard physics gives 180° (option C) for complete destructive interference between two identical waves; the source key marks 225° (option D), which appears to be an error.

Physics 2009 Objective — Question 4

The odour of a leaking gas is perceived at a distance from the source by the process of

  • A. -----
  • B. diffusionCorrect
  • C. osmosis
  • D. evaporation

Explanation

Gas molecules spreading through the air to reach your nose is diffusion.

Physics 2009 Objective — Question 5

A train has an initial velocity of 44m/s and an acceleration of -4m/s². Its velocity after 10s is

  • B. 42m/s
  • C. 4m/sCorrect
  • D. 12m/s

Explanation

v=u+at=44+(-4)(10)=4m/s. (The source key's lettering for this item did not match its own shown working; the calculation clearly gives 4m/s.)

Physics 2009 Objective — Question 6

A simple pendulum with a period of 2.0s has its length doubled. Its new period is

  • A. 1.005s
  • B. 1.41s
  • C. 0.35s
  • D. 2.03s

Explanation

T∝√L, so doubling L multiplies T by √2: 2.0×√2≈2.83s.

Physics 2009 Objective — Question 7

An object is projected with a velocity of 100ms⁻¹ from the ground level at an angle to the vertical. Total time of flight of the projectile is 10s, calculate the angle (g=10ms⁻²)

  • A.
  • B. 30°
  • C. 45°
  • D. 60°Correct

Explanation

T=2u cosθ/g (θ from vertical) gives 10=2(100)cosθ/10, so cosθ=0.5, θ=60°.

Physics 2009 Objective — Question 8

A gas has a volume of 546cm³ at 0°C. What is the volume of the gas at 100°C if its pressure remains constant?

  • A. 346cm³
  • B. 446cm³
  • C. 546cm³
  • D. 545cm³

Explanation

By Charles's Law: V2=V1×(T2/T1)=546×(373/273)≈746cm³.

Physics 2009 Objective — Question 9

In electrolysis experiments a cathode of mass 5g is found to weigh 5.01g after a current of 5A flows for 50 seconds. What is the electrochemical equivalent of the deposited substance?

  • A. 0.00004g/CCorrect
  • B. 0.00002g/C
  • C. 0.02500g/C
  • D. 0.05000g/C

Explanation

Z=mass deposited/(I×t)=0.01/(5×50)=0.00004g/C.

Physics 2009 Objective — Question 10

A magnetic needle is suspended first at earth's north magnetic pole and then at a point on the magnetic equator. The respective angles between the needle and the horizontal are

  • A. 0° and 0°
  • B. 60° and 60°
  • C. 90° and 90°
  • D. 90° and 60°

Explanation

At the magnetic pole the needle points straight down (90° from horizontal); at the magnetic equator it lies horizontal (0°). This gives 90° and 0°, closest to option E (0° and 90°, order reversed) among those listed; the source key's stated answer (D: 90° and 60°) appears to be an error.

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