Post-UTME Physics 2009 Objective — Question 5

Question 5 of 10 from the Post-UTME Screening (Post-UTME) Physics 2009 Objective paper, with the correct answer and a full explanation.

A train has an initial velocity of 44m/s and an acceleration of -4m/s². Its velocity after 10s is

Explanation

v=u+at=44+(-4)(10)=4m/s. (The source key's lettering for this item did not match its own shown working; the calculation clearly gives 4m/s.)

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