All 20 questions from the Post-UTME Screening (Post-UTME) Physics 2018 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.
In a simple cell, a defect known as polarization is due to the
A. deposition of zinc on the anode
B. dissolution of zinc in the electrolyte
C. collection of hydrogen bubbles at the cathode/positive plateCorrect
D. impurities in the electrolyte
Explanation
Polarization in a simple cell is caused by a layer of hydrogen bubbles building up on the copper (positive) plate, which increases internal resistance and reduces the cell's e.m.f.
A battery of e.m.f. 10V and internal resistance 2 ohm is connected to an external resistance of 3 ohm. Determine the potential drop across the 2 ohm (internal) resistance.
A. 2V
B. 3V
C. 4VCorrect
D. 5V
Explanation
Current I = emf/(R+r) = 10/(3+2) = 2A. Potential drop across internal resistance = I x r = 2 x 2 = 4V.
What is the resistance of a wire 220cm long and 0.7mm in diameter at 20 degrees C? (The resistivity of the material at 20 degrees C is 3.5x10^-6 ohm.cm)
A. 0.20 ohmCorrect
B. 5.00 ohm
C. 0.20 ohm (variant)
D. 5.00 ohm (variant)
Explanation
Radius = 0.035cm. Area = pi*r^2 = pi*(0.035)^2 = 0.003848 cm^2. R = (resistivity x length)/area = (3.5x10^-6 x 220)/0.003848 = 0.20 ohm.
226-88-Ra -> X + 222-86-Rn. In the above nuclear equation, X represents
A. an electron
B. an alpha particleCorrect
C. a beta particle
D. a gamma ray
Explanation
Mass number balance: 226 = A(X) + 222, so A(X)=4. Atomic number balance: 88 = Z(X) + 86, so Z(X)=2. A particle with mass number 4 and atomic number 2 is an alpha particle.
Which of the following is TRUE of cathode rays? I. They travel in straight lines. II. They can be deflected by electric and magnetic fields. III. They are negatively charged particles called electrons.
A. I and II only
B. I and III only
C. II and III only
D. I, II and IIICorrect
Explanation
All three statements correctly describe cathode rays: they travel in straight lines, can be deflected by electric/magnetic fields, and are streams of electrons.
A virtual image of an object was obtained at a distance of 30.0 cm from a converging lens of focal length 20.0cm. What is the distance of the object from the lens?
A. 30.0cm
B. 12.0cmCorrect
C. 10.0cm
D. 7.5cm
Explanation
For a virtual image, v=-30cm, f=20cm. Using 1/v-1/u=1/f: -1/30-1/u=1/20, giving u=-12cm, so object distance is 12.0cm.
Use the diagram above (a converging lens with 2F', F', F and 2F marked) to answer this question. Where must an object be placed so that an inverted but enlarged image can be formed?
A. Between the lens and F
B. At F
C. Beyond 2F
D. Between F' and 2F'Correct
Explanation
An object placed between F and 2F (on the object side, F' and 2F') produces a real, inverted, magnified image beyond 2F on the other side.
Use the figure above (three overlapping circles labelled RED, GREEN and BLUE, with the central overlap region labelled H) to answer this question. In the figure above, what is the colour of the region of intersection of the red, green and blue circles labelled H?
A. Yellow
B. Magenta
C. WhiteCorrect
D. Cyan
Explanation
The overlap of all three primary colours of light (red, green and blue) produces white light.
Which of the following statements about a charged electroscope are correct? I. when a negatively charged object is brought close to a negatively charged electroscope, the divergence increases. II. When a positively charged object is brought close to a negatively charged electroscope, the divergence decreases. III. When an uncharged object is brought close to a negatively charged electroscope, the divergence decreases.
A. I and II onlyCorrect
B. II and III only
C. I and III only
D. I, II and III
Explanation
Bringing a like (negative) charge closer increases divergence (repulsion); bringing an opposite (positive) charge closer decreases divergence; an uncharged object has negligible direct effect (statement III is not generally correct).