Post-UTME Physics 2018 Objective — Question 2
Question 2 of 20 from the Post-UTME Screening (Post-UTME) Physics 2018 Objective paper, with the correct answer and a full explanation.
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The distance between two successive crests of a wave is 25.0 cm and the velocity of the wave is 275.0ms-1. What is the frequency of the wave?
- A. 11Hz
- B. 1050Hz
- C. 1100HzCorrect
- D. 6875 Hz
Explanation
Wavelength = 25.0cm = 0.25m. Frequency = v/lambda = 275/0.25 = 1100Hz.
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