WAEC Biology 2014 Theory — Question 15
Question 15 of 23 from the West African Examinations Council (WAEC) Biology 2014 Theory paper, with the correct answer and a full explanation.
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4(b). A man whose blood group is heterozygous A is married to a woman whose blood group is AB. With the aid of a genetic diagram, suggest the possible blood groups of their children.
Model answer
Father's genotype: IᴬIᵒ (heterozygous A). Mother's genotype: IᴬIᴮ (AB). Father's gametes: Iᴬ, Iᵒ. Mother's gametes: Iᴬ, Iᴮ. Punnett square: Iᴬ×Iᴬ = IᴬIᴬ (Group A) Iᴬ×Iᴮ = IᴬIᴮ (Group AB) Iᵒ×Iᴬ = IᴬIᵒ (Group A) Iᵒ×Iᴮ = IᴮIᵒ (Group B) Possible blood groups of the children: A, AB, and B (in the ratio 2 A : 1 AB : 1 B).
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