WAEC Chemistry 2010 Objective — Question 19
Question 19 of 49 from the West African Examinations Council (WAEC) Chemistry 2010 Objective paper, with the correct answer and a full explanation.
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A solution of sodium trioxocarbonate (IV) contains 10.6 g in 250cm³ of solution. Calculate the concentration of the solution. [Na2CO3=106]
- A. A. 0.4mol dm⁻³Correct
- B. B. 1.0 mol dm⁻³
- C. C. 10.6 mol dm⁻³
- D. D. 25.0 mol dm⁻³
Explanation
Mole = Mass/Molar mass = 10.6g/106gmol⁻¹ = 0.1 mol. Concentration = Mole/Volume(dm³) = 0.1mol/0.25dm³ = 0.4 moldm⁻³.
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