WAEC Chemistry 2025 Objective — Question 22

Question 22 of 50 from the West African Examinations Council (WAEC) Chemistry 2025 Objective paper, with the correct answer and a full explanation.

The number of moles of KOH present in 200cm3 of 5.6 g dm-3 solution is [KOH = 56 g mol-1]

A. 2.01
B. 1.12
C. 0.02Correct
D. 0.01

Explanation

Concentration = 5.6 g/dm3, Volume = 200 cm3 = 0.2 dm3. Mass of KOH = 5.6 g/dm3 x 0.2 dm3 = 1.12 g. Molar mass of KOH = 56 g/mol. Mole = mass/molar mass = 1.12/56 = 0.02 mol.

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