Question

PART I (FOR CANDIDATES IN NIGERIA, SIERRA LEONE AND THE GAMBIA)
1. A stone is projected vertically upward with a speed of 30 ms⁻¹ from the top of a tower of height 50 m. Neglecting air resistance, determine the maximum height it reached from the ground. [g = 10 ms⁻²]

Accepted Answer

The stone is projected vertically upwards, so its initial speed is entirely vertical: uy=30m/s. Height of tower, H1=50m.
Maximum height reached from the point of release, H2 = uy²/(2g) = 30²/(2x10) = 900/20 = 45m.
Maximum height reached from the ground = H1+H2 = (50+45)m = 95m.

WAEC Physics 2010 Theory — Question 1

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