JAMB Biology 2015 Objective — Question 28
Question 28 of 50 from the Joint Admissions and Matriculation Board (JAMB) Biology 2015 Objective paper, with the correct answer and a full explanation.
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A chemical reaction with entropy change of +20 Jk⁻¹ and free energy change +55000J occurred at −23°C. Calculate the enthalpy change.
- A. 55460J
- B. 44540J
- C. 50000J
- D. 60000JCorrect
Explanation
ΔG = ΔH − TΔS ⟹ ΔH = ΔG + TΔS = 55000 + (250×20) = 55000+5000 = 60000J.
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