JAMB Chemistry 2008 Objective — Question 24

Question 24 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2008 Objective paper, with the correct answer and a full explanation.

In recharging a lead-acid accumulator, the reaction at the cathode can be represented as

A. Pb2+(aq)+SO42-(aq) -> PbSO4(s)
B. Pb2+(aq)+2e- -> Pb(s)Correct
C. Pb2+(aq)+2H2O(l) -> PbO2(s)+4H+(aq)+4e-
D. Pb(s) -> Pb2+(aq)+2e-

Explanation

When the battery is discharging, i.e. delivering a current, the lead at the anode is oxidized: Pb -> Pb2+ + 2e-. This equation is same for the reaction that occurs at the cathode when the battery is being recharged (reverse: anode discharging equals cathode recharging), giving Pb2+(aq)+2e- -> Pb(s).

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