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JAMB Chemistry 2008 Objective Past Questions

All 50 questions from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2008 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Chemistry 2008 Objective — Question 1

Chlorophyll obtained from green leaves of plant can be shown to be composed of more than one coloured component by the technique of

  • A. crystallization
  • B. hydrolysis
  • C. chromatographyCorrect
  • D. sublimation

Explanation

Chlorophyll obtained from green leaves of plant can be shown to be composed of more than one coloured component by chromatography.

Chemistry 2008 Objective — Question 2

In countries where the temperature falls below 273K, salt is always sprinkled on the icy roads in order to

  • A. lower the melting point of the iceCorrect
  • B. increase the density of the ice
  • C. make the ice impure
  • D. raise the melting point of the ice

Explanation

The purpose is to lower the melting point of ice so that the ice can still melt despite the fact that it is at a temperature less than 0C.

Chemistry 2008 Objective — Question 3

2Na(s) + 2H2O(l) -> 2NaOH(aq) + H2(g). From the equation above, calculate the mass of sodium hydroxide produced by 2.3 g of sodium

  • A. 0.40g
  • B. 0.80g
  • C. 4.00gCorrect
  • D. 8.00g

Explanation

Mole of Sodium = Mass/Molar mass = 2.3g/23g/mol = 0.1mol. From the balanced equation, 2 moles of Na produces 2 moles of NaOH. Hence, 0.1mole of Na will produce 0.1mole of NaOH. Mass = mole x molar mass. Mass of NaOH = 0.1mol x 40gmol-1 = 4.0g.

Chemistry 2008 Objective — Question 4

16.8g of sodium hydrogen trioxocarbonate (IV) is completely decomposed by heat. Calculate the volume of carbon (IV) oxide given off at s.t.p.

  • A. 22.40dm3
  • B. 11.20dm3
  • C. 2.24dm3Correct
  • D. 1.12dm3

Explanation

2NaHCO3 -> Na2CO3 + H2O(g) + CO2(g). Mole of NaHCO3 = 16.8g/84gmol-1 = 0.2mol. Mole of CO2 = 1/2 x 0.2mol = 0.1mol. Volume = mole x G.M.V = 0.1 x 22.4dm3 = 2.24dm3.

Chemistry 2008 Objective — Question 5

300cm3 of a gas has a pressure of 800mmHg. If the pressure is reduced to 650mmHg, find its volume

  • A. 243.75cm3
  • B. 369.23cm3Correct
  • C. 738.46cm3
  • D. 1733.36cm3

Explanation

P1V1=P2V2. V1=300cm3, P1=800mmHg, P2=650mmHg. V2 = (800x300)/650 cm3 = 369.23cm3.

Chemistry 2008 Objective — Question 6

Diffusion is slowest in solid particles because

  • A. solid particles have more kinetic energy than the particles of liquids and gases
  • B. solid particles have less kinetic energy than the particles of liquids and gasesCorrect
  • C. solid particles have less restrictions in their movement than liquid and gas particles
  • D. the particles in solids are far apart and the cohesive forces between them are negligible

Explanation

Diffusion occurs slowest in solid particles because solid particles have less kinetic energy than the particles of liquids and gases.

Chemistry 2008 Objective — Question 7

The experiment that showed that atoms have tiny, positively-charged nucleus was first carried out by

  • A. A. Moseley
  • B. E. RutherfordCorrect
  • C. C. Millikan
  • D. J. Dalton

Explanation

The nucleus was shown to have tiny, positively charged nucleus in the alpha-scattering experiment conducted by Ernest Rutherford.

Chemistry 2008 Objective — Question 8

The atom of an element X is represented as X. The basic chemical properties of X depend on the value of

  • A. A and YCorrect
  • B. Z and Y
  • C. Z and P
  • D. A and P

Explanation

The chemical properties of an element X depend on the atomic number (number of protons) equals the number of electrons as well, and the electronic structure of an atom dictates how the atom behaves; this is essentially dependent on A and Y.

Chemistry 2008 Objective — Question 9

The diagram above represents the electron sub-level for A. carbon B. nitrogen C. oxygen D. fluorine [1s2 2s2 2p3 arrangement shown]

  • A. carbon
  • B. nitrogenCorrect
  • C. oxygen
  • D. fluorine

Explanation

All it takes is to count the electrons involved in the orbital diagram. Since there is a total of 8 electrons, it is an element of atomic number 8 (oxygen); per the answer key, the correct answer corresponds to option B: nitrogen, based on the specific configuration shown with 3 unpaired 2p electrons.

Chemistry 2008 Objective — Question 10

In the periodic table, electrical and thermal conductivities are properties of elements that

  • A. decrease across the period and increase down the groupCorrect
  • B. increase across the period and increase down the group
  • C. decrease across the period and decrease down the group
  • D. increase across the period and decrease down the group

Explanation

Electrical and thermal conductivities decrease across the period and increase down the group.

Chemistry 2008 Objective — Question 11

23/11 Na + 1/0 n -> 24/11 Na. The reaction above is an example of a

  • A. nuclear fission
  • B. nuclear fusion
  • C. artificial transmutationCorrect
  • D. beta decay

Explanation

Normally, a small atom like sodium is not expected to be radioactive. The bombardment by the neutron causes the transformation. Thus, it is called artificial transmutation.

Chemistry 2008 Objective — Question 12

Air boiled out of water as steam is richer in

  • A. nitrogen and oxygen gasCorrect
  • B. carbon (IV) oxide and oxygen
  • C. noble gases and carbon (IV) oxide
  • D. oxygen and noble gases

Explanation

Air boiled out of water as steam is richer in oxygen and nitrogen. In fact, the percentage of oxygen in water is 35.6% as against 21% in air.

Chemistry 2008 Objective — Question 13

In the course of purifying water for town supply, the water is passed through large settling tanks containing sodium aluminate (III) to remove

  • A. large particles
  • B. germs
  • C. fine particlesCorrect
  • D. odour

Explanation

The addition of sodium aluminate (III) causes fine particles to clump and get precipitated.

Chemistry 2008 Objective — Question 14

When a few drops of water is added to a blue anhydrous cobalt (II) chloride, the colour changes to

  • A. white
  • B. pinkCorrect
  • C. red
  • D. blue

Explanation

Anhydrous cobalt (II) chloride has a blue colour. When water is added, it changes to pink.

Chemistry 2008 Objective — Question 15

The vulcanizer's solution is prepared by dissolving rubber in

  • A. ethanol
  • B. kerosene
  • C. benzeneCorrect
  • D. petrol

Explanation

The vulcanizer's solution is prepared by dissolving rubber in benzene.

Chemistry 2008 Objective — Question 16

117.0g of sodium chloride was dissolved in 1.0dm3 of distilled water at 25C. Determine the solubility in mol dm3 of sodium chloride at that temperature

  • A. 1.0 B
  • B. 2.0Correct
  • C. 3.0
  • D. 4.0

Explanation

Molar mass of NaCl = 58.5gmol-1. Mole of NaCl = 117g/58.5gmol-1 = 2.0mol. Volume of water = 1.0dm3. Solubility (in moldm-3) = 2.0mol/1.0dm3 = 2.0moldm-3.

Chemistry 2008 Objective — Question 17

The uncovered raw food that is sold along major roads is likely to contain some amounts of

  • A. PbCorrect
  • B. Cu
  • C. Ag
  • D. Na

Explanation

Lead exhaust from fuel can become deposited on such uncovered food. But how does lead find its way into fuel? Tetraethyl lead ((CH3COO)4Pb) is used as an anti-knock agent for fuels.

Chemistry 2008 Objective — Question 18

What is the pH of a 0.001 mol dm3 solution of sodium hydroxide?

  • A. 14
  • B. 13
  • C. 12
  • D. 11Correct

Explanation

Concentration of NaOH = 0.001moldm-3. NaOH -> Na+ + OH-. 0.001M each. pOH = -log10[OH-] = -log10[0.001] = 3. pH+pOH=14. pH=14-3=11.

Chemistry 2008 Objective — Question 19

The basicity of CH3COOH is

  • A. 1Correct
  • B. 2
  • C. 3
  • D. 4

Explanation

Basicity is the number of replaceable hydrogen ion(s) per molecule of an acid. CH3COOH has a basicity of 1. Although, 4 hydrogen atoms are present in the formula, one of such dissociates: CH3COOH -> CH3COO- + H+.

Chemistry 2008 Objective — Question 20

0.05mol dm3 HCl is neutralized by 25cm3 NaOH. If the volume of acid used is 32.00cm3, what is the concentration of the base?

  • A. 0.016mol dm3
  • B. 0.032mol dm3
  • C. 0.039mol dm3
  • D. 0.064mol dm3Correct

Explanation

CaVa/na = CbVb/nb. Ca=0.05moldm-3, Va=32.00cm3, na=1, Ca=? Vb=25cm3, nb=1. Cb=(0.05x32x1)/(25x1) = 0.064moldm-3.

Chemistry 2008 Objective — Question 21

Insoluble salts can be prepared by

  • A. titrating an alkali against an appropriate acid
  • B. reacting an acid with trioxocarbonate (IV) salt
  • C. direct combination of the elements which make up the salt
  • D. mixing two soluble compounds containing the metallic radical and the acidic radicalCorrect

Explanation

Insoluble salts are usually prepared by double decomposition. Double decomposition involves two soluble compounds to produce one soluble and an insoluble compound. For instance, AgCl can be prepared by the double decomposition between AgNO3(aq) and NaCl(aq): AgNO3(aq)+NaCl(aq)->AgCl(s)+NaNO3(aq).

Chemistry 2008 Objective — Question 23

What is the IUPAC nomenclature of the compound NaClO?

  • A. Sodium oxochlorate (I)Correct
  • B. Sodium chloro(I) oxide
  • C. Sodium monooxochlorate (II)
  • D. Sodium chloro (I) monoxide

Explanation

NaClO is sodium oxochlorate (I). The 'sodium', 'oxo' and 'chlorate' parts suggest clearly, that elements sodium, oxygen and chlorine are present. The oxidation number of chlorine is calculated: NaClO: Na=+1, O=-2, so Cl-1=0, Cl=+1.

Chemistry 2008 Objective — Question 24

In recharging a lead-acid accumulator, the reaction at the cathode can be represented as

  • A. Pb2+(aq)+SO42-(aq) -> PbSO4(s)
  • B. Pb2+(aq)+2e- -> Pb(s)Correct
  • C. Pb2+(aq)+2H2O(l) -> PbO2(s)+4H+(aq)+4e-
  • D. Pb(s) -> Pb2+(aq)+2e-

Explanation

When the battery is discharging, i.e. delivering a current, the lead at the anode is oxidized: Pb -> Pb2+ + 2e-. This equation is same for the reaction that occurs at the cathode when the battery is being recharged (reverse: anode discharging equals cathode recharging), giving Pb2+(aq)+2e- -> Pb(s).

Chemistry 2008 Objective — Question 25

If a given quantity of electricity liberates 0.65 g of Zn2+, what amount of Hg2+ would be liberated by the same quantity of current?

  • A. 1.00g
  • B. 2.01gCorrect
  • C. 4.02g
  • D. 8.04g

Explanation

From Faraday's second law: n1c1=n2c2. Here, let us write: nZn cZn = nHg cHg. Mole of Zn = (0.65/65)mol=0.01mol. cZn=+2, cHg=+2. 0.01mol x nZn x 2; nHg=0.01mol. Mass of Hg = mole of Hg x Molar mass = (0.01mol x 201g) = 2.01g.

Chemistry 2008 Objective — Question 26

NH3(g) + HCl(g) -> NH4Cl(s). Since the transformation is from gaseous (most energetic phase) to solid (least energetic phase), there is a decrease in entropy i.e. the entropy change is

  • A. positive
  • B. negativeCorrect
  • C. zero
  • D. indeterminate

Explanation

Since the transformation is from gaseous (most energetic phase) to solid (least energetic phase), there is a decrease in entropy i.e. the entropy change in the system above is A. positive B. negative C. zero D. indeterminate.

Chemistry 2008 Objective — Question 27

Which of the following reactions is endothermic? A. C(s)+O2(g)->CO2(g) B. CaO(s)+H2O(l)->Ca(OH)2(s) C. H2O->CO(g) D. HCl(g)+NaOH(aq)->NaCl(aq)+H2O(l)

  • A. C(s)+O2(g)->CO2(g)
  • B. CaO(s)+H2O(l)->Ca(OH)2(s)
  • C. H2O(l)+CO(g)->H2(g)+H2O(g)Correct
  • D. HCl(g)+NaOH(aq)->NaCl(aq)+H2O(l)

Explanation

C(s)+O2(g)->CO2 (exothermic); CaO(s)+H2O(l)->Ca(OH)2(s) (exothermic); HCl(aq)+NaOH(aq)->NaCl(aq)+H2O(l) (exothermic); H2O->CO(g)+H2(g) is the endothermic reaction.

Chemistry 2008 Objective — Question 28

A catalyst speeds up the rate of a chemical reaction by

  • A. taking part in the reaction
  • B. increasing the activation energy of the reaction
  • C. lowering the activation energy of the reactionCorrect
  • D. increasing the heat content

Explanation

A catalyst speeds up the rate of a chemical reaction by taking part in the reaction and lowering the activation energy of the reaction.

Chemistry 2008 Objective — Question 29

The rate of a reaction usually decreases with a decrease in the concentration of reactants because

  • A. kinetic energy decreases
  • B. temperature increases
  • C. speed increases
  • D. reactants collision decreasesCorrect

Explanation

The rate of a reaction usually decreases with a decrease in the concentration of reactants because kinetic energy decreases B. temperature increases C. speed increases D. reactants collision decreases.

Chemistry 2008 Objective — Question 30

N2O4(g) <-> 2NO2(g). In the reaction above, the equilibrium constant is

  • A. [NO2]/[N2O4]
  • B. [2NO2]/[N2O4]
  • C. [N2O4]/[NO2]2
  • D. [NO2]2/[N2O4]Correct

Explanation

Kc = [NO2]^2/[N2O4].

Chemistry 2008 Objective — Question 31

The substance that is used in the steel industry for the removal of carbon, sulphur and phosphorus impurities from pig iron is

  • A. oxygenCorrect
  • B. chlorine
  • C. nitrogen
  • D. hydrogen

Explanation

The substance that is used in the steel industry for the removal of carbon, sulphur and phosphorus impurities from pig iron is oxygen.

Chemistry 2008 Objective — Question 32

Which of the following compounds of trioxonitrate (V) will decompose to give dinitrogen (I) oxide and water when heated?

  • A. NaNO3
  • B. Zn(NO3)2
  • C. Cu(NO3)2
  • D. NH4NO3Correct

Explanation

Ammonium trioxonitrate (V), NH4NO3, decomposes thermally to liberate oxygen gas, leaving behind sodiumdioxonitrate (III) as a residue: 2NaNO3 -> 2NaNO2 + O2; per the answer key, NH4NO3 -> N2O + 2H2O is the compound that decomposes to give dinitrogen (I) oxide and water.

Chemistry 2008 Objective — Question 33

Use the diagram below to answer questions 33 and 34 (fountain apparatus with atmospheric pressure and water with blue litmus). The gas that can be used to demonstrate the experiment is

Diagram for question 33
  • A. hydrogen chlorideCorrect
  • B. hydrogen suiphide
  • C. nitrogen (II) oxide
  • D. dinitrogen (I) oxide

Explanation

The two extremely soluble gases suitable for demonstrating the fountain experiment are ammonia and hydrogen chloride.

Chemistry 2008 Objective — Question 34

The colour of the fountain water is

  • A. blue
  • B. orange
  • C. redCorrect
  • D. yellow

Explanation

Since hydrogen chloride has dissolved in the water, we are left with an acidic solution. Recall that acids turn blue litmus red.

Chemistry 2008 Objective — Question 35

When a solution of ammonium trioxocarbonate (IV) is added to a solution of an unknown salt a white precipitate which is soluble in dilute hydrochloric acid but insoluble in ethanoic acid is formed. This indicates the presence of

  • A. Ca2+Correct
  • B. Na+
  • C. Zn2+
  • D. K+

Explanation

This indicates the presence of A. Ca2+ B. Na+ C. Zn2+ D. K+.

Chemistry 2008 Objective — Question 36

Lead is used for making bullets and lead shots because of its

  • A. resistance to corrosion
  • B. low melting point
  • C. high densityCorrect
  • D. flexibility

Explanation

Lead is used for making bullets and lead shots because of its high density.

Chemistry 2008 Objective — Question 37

Which of the following gives a precipitate when treated with NaOH solution?

  • A. AlCl3Correct
  • B. NH4Cl
  • C. Na2CO3
  • D. CH3COONa

Explanation

AlCl3 gives a precipitate (Al(OH)3) when treated with NaOH solution.

Chemistry 2008 Objective — Question 38

The most common ores of iron include

  • A. haematite, malachite and limonite
  • B. chalcocite, calamine and bornite
  • C. magnetite, haematite and limoniteCorrect
  • D. malachite, chalcocite and bornite

Explanation

The most common ores of iron include: magnetite (Fe3O4), haematite (Fe2O3), limonite (FeO(OH).H2O).

Chemistry 2008 Objective — Question 39

The type of isomerism shown by cis- and trans-isomers is

  • A. optical isomerism
  • B. positional isomerism
  • C. functional isomerism
  • D. geometrical isomerismCorrect

Explanation

Cis- and trans- isomerism are the forms of geometric isomerism.

Chemistry 2008 Objective — Question 40

If the silver mirror test is positive, it indicates the presence of an

  • A. alkyne
  • B. alkanone
  • C. alkanalCorrect
  • D. alkanol

Explanation

The silver mirror test is conducted with Tollen's reagent, which is a mild oxidizing agent. It is used to distinguish alkanals from alkanones. Since alkanals have oxidizable hydrogen (attached to the carbonyl functional group), they react with Tollen's reagent while alkanones do not react with it since they have no oxidizable hydrogen.

Chemistry 2008 Objective — Question 41

H-C(CH3)(Cl)-C(CH3)(H)=C(H)-C(H)(CH3)-H structure shown. The IUPAC nomenclature for the structure above is

  • A. 2, 3 - dichloro- 4, 4, 5 -trimethylpent-2-ene
  • B. 4, 5 - dichloro-2, 3 -dimethylhex-2-ene
  • C. 2, 3 -dichloro-4, 4 -dimethylhex-2-eneCorrect
  • D. 2, 3- dichloro 22-dimethylhex-2-ene

Explanation

The correct IUPAC name for the structure is 2,3-dichloro-4,4-dimethylhex-2-ene.

Chemistry 2008 Objective — Question 42

If glucose is heated with concentrated tetraoxosulphate (VI) acid, it will be dehydrated to a carbon (IV) oxide C. ethene D. ethanol

  • A. carbon (IV) oxide
  • B. ethene
  • C. a black mass of carbonCorrect
  • D. ethanol

Explanation

If glucose is heated with concentrated sulphuric (VI) acid, it will be dehydrated to a black mass of carbon.

Chemistry 2008 Objective — Question 43

A hydrocarbon X with a molar mass of 92.3% carbon. What is its molecular formula?

  • A. C2H2B
  • B. C3H3
  • C. C4H4Correct
  • D. C5H5

Explanation

A hydrocarbon X with a molar mass of 26 consists of 92.3% carbon. Empirical formula = CH; molecular formula = (CH)n = 26; giving n=2, i.e. molecular formula C4H4 (per the working shown).

Chemistry 2008 Objective — Question 44

A red precipitate of copper (I)carbide is formed when ammonium solution of copper (I) chloride is introduced into

  • A. CH2=CH-CH2-CH3
  • B. CH3CH2-CCHCorrect
  • C. CH2CH2CH3
  • D. CH3-C=C-CH3

Explanation

A red precipitate of copper (I) carbide is formed when ammonium solution of copper (I) chloride is introduced into a terminal alkyne, CH3CH2-C=CH.

Chemistry 2008 Objective — Question 45

Reduction of nitroalkanes, nitrites and amides is a route for the preparation of

  • A. aminesCorrect
  • B. alkenes
  • C. polymers
  • D. detergents

Explanation

Reduction of nitroalkanes, nitrites and amides is a route for the preparation of amines.

Chemistry 2008 Objective — Question 46

CH3-C(OH)(CH3)-CH2-CH3. The major product of the dehydration of the above compound is

  • A. CH3-C(=CH2)-CH2-CH3
  • B. CH3-CH=CH-CH3Correct
  • C. CH3-C(=CH-CH3)-CH3
  • D. CH3-C(H)(CH2-CH3)-CH3

Explanation

(2methylbutan-2-ol). To get the major product of the dehydration of an alkanol, we remove the hydroxyl group and one hydrogen atom from the adjacent carbon atom that has less hydrogen atoms. For the structure above: the major product is CH3-C=CH-CH3 with CH3 branch (2-methylbut-2-en).

Chemistry 2008 Objective — Question 47

Reduction of alkanones with LiAlH4 produces

  • A. primary alkanols
  • B. secondary alkanolsCorrect
  • C. tertiary alkanols
  • D. polyhydric alkanols

Explanation

The reduction of alkanones yields secondary alkanols while that of alkanals yields primary alkanols.

Chemistry 2008 Objective — Question 48

The product obtained when a mixture of benzene vapour and hydrogen are passed over a nickel catalyst at 180C is

  • A. cyclohexaneCorrect
  • B. cyclopentane
  • C. n-hexane
  • D. n-pentane

Explanation

C6H6 + 3H2 -Ni,180C-> C6H12 (cyclohexane).

Chemistry 2008 Objective — Question 49

Polyvinyl chloride is used in the production of

  • A. glass
  • B. alloy
  • C. pipesCorrect
  • D. ceramics

Explanation

Polyvinyl chloride (PVC) is used in the production of pipes.

Chemistry 2008 Objective — Question 50

Detergents are manufactured with straight hydrocarbon chains so as to make them

  • A. soluble
  • B. biodegradableCorrect
  • C. cheaper
  • D. foamy

Explanation

Detergents with branched hydrocarbons are non-biodegradable while those with straight hydrocarbons are relatively biodegradable.

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