JAMB Chemistry 2008 Objective — Question 3
Question 3 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2008 Objective paper, with the correct answer and a full explanation.
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2Na(s) + 2H2O(l) -> 2NaOH(aq) + H2(g). From the equation above, calculate the mass of sodium hydroxide produced by 2.3 g of sodium
- A. 0.40g
- B. 0.80g
- C. 4.00gCorrect
- D. 8.00g
Explanation
Mole of Sodium = Mass/Molar mass = 2.3g/23g/mol = 0.1mol. From the balanced equation, 2 moles of Na produces 2 moles of NaOH. Hence, 0.1mole of Na will produce 0.1mole of NaOH. Mass = mole x molar mass. Mass of NaOH = 0.1mol x 40gmol-1 = 4.0g.
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