JAMB Chemistry 2010 Objective — Question 22

Question 22 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2010 Objective paper, with the correct answer and a full explanation.

22. 6AgNO3(aq) + PH3(g) + 3H2O(l) -> 6Ag(s) + H3PO3(aq) + 6HNO3(aq). In the reaction above, the reducing agent is A. PH3(g) B. AgNO3(aq) C. HNO3(aq) D. H2O(l)

A. PH3(g)Correct
B. AgNO3(aq)
C. HNO3(aq)
D. H2O(l)

Explanation

The oxidation number of silver decreased from +1 (in AgNO3) to 0 in Ag; this is reduction, so AgNO3 is the oxidizing agent. The oxidation number of Phospho in PH3 increased to +4 (from PH3 to H3PO3); this is oxidation, so PH3 is the reducing agent.

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