JAMB Chemistry 2010 Objective — Question 25

Question 25 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2010 Objective paper, with the correct answer and a full explanation.

25. What quantity of aluminium is deposited when a current of 10A is passed through a solution of an aluminium salt for 1930s? A. 5.4g B. 14.2g C. 0.2g D. 1.8g [Al=27, F=96500 C mol-1]

A. 5.4g
B. 14.2g
C. 0.2g
D. 1.8gCorrect

Explanation

Al3+ + 3e- -> Al. 1 mole of Al (27g) requires 3F (289500C). Charge passed = 10A x 1930s = 19300C. Mass deposited = 19300/289500 x 27g = 1.8g.

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