JAMB Chemistry 2011 Objective — Question 17
Question 17 of 49 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2011 Objective paper, with the correct answer and a full explanation.
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CH3COOH(aq)+OH(aq) ⇌ CH3COO(aq)+H2O(l). In the reaction above, CH3COO(aq) is the
- A. A. conjugate acid
- B. B. conjugate baseCorrect
- C. C. acid
- D. D. base
Explanation
A Bronsted-Lowry acid donates a proton, while the base accepts a proton. A conjugate acid-base pair differ by a proton. CH3COOH and CH3COO constitute a conjugate acid-base pair, with CH3COO as the conjugate base.
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