JAMB Chemistry 2011 Objective — Question 29
Question 29 of 49 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2011 Objective paper, with the correct answer and a full explanation.
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Given that M is the mass of a substance deposited during electrolysis and Q is the quantity of electricity consumed, then Faraday's first law can be written as [E=Electrochemical equivalent]
- A. A. M=E/Q
- B. B. M=E/Q
- C. C. M=EQCorrect
- D. D. M=Q/E
Explanation
Faraday's first law states that the mass deposited is directly proportional to the quantity of electricity: M=EQ, where E is the electrochemical equivalent.
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