JAMB Chemistry 2012 Objective — Question 21
Question 21 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2012 Objective paper, with the correct answer and a full explanation.
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During a titration experiment, 0.05 moles of carbon(IV) oxide is liberated. What is the volume of gas liberated? [Molar volume of a gas at s.t.p.=22.4dm³]
- A. 22.40dm³
- B. 11.20dm³
- C. 2.24dm³
- D. 1.12dm³Correct
Explanation
Volume = Mole × GMV = 0.05×22.4 = 1.12dm³.
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