Free account: track your progress — Sign up free

JAMB Chemistry 2012 Objective — Question 27

Question 27 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2012 Objective paper, with the correct answer and a full explanation.

Advertisement

CO(g) +H2O(g)→ CO2(g)+H2(g). Calculate the standard heat change of the reaction above, if the standard enthalpies of formation of CO2(g), H2O and CO(g) in kJ mol⁻¹ are -394, -242 and -110 respectively.

  • A. +262kJ mol⁻¹
  • B. -262kJ mol⁻¹
  • C. +42kJ mol⁻¹
  • D. -42kJ mol⁻¹Correct

Explanation

ΔH = ΣH(products) − ΣH(reactants) = −394 − (−352) = −42kJ mol⁻¹, where ΣH(reactants) = −110+(−242) = −352.

Advertisement

Sign up free to unlock

  • Score tracking
  • Practice history
  • Saved questions
  • Progress dashboard
  • Personalized sessions
  • Weak-topic breakdown

…and/or go further with premium services and No Ads.