JAMB Chemistry 2013 Objective — Question 29

Question 29 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2013 Objective paper, with the correct answer and a full explanation.

In the graph above, the activation energy of the catalyzed reaction is

A. 250kJ
B. 200kJ
C. 100kJCorrect
D. 300kJ

Explanation

The lower of the two curves is always the profile diagram of the catalysed reaction. For the catalyzed reaction, activation energy = 200kJ − 100kJ = 100kJ.

Sign up free to unlock

Score tracking
Practice history
Saved questions
Progress dashboard
Personalized sessions
Weak-topic breakdown

…and/or go further with premium services and No Ads.

Create free account

More questions from Chemistry 2013 Objective More Chemistry past papers