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JAMB Chemistry 2013 Objective — Question 41

Question 41 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2013 Objective paper, with the correct answer and a full explanation.

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The decarboxylation of ethanoic acid will produce carbon(IV) oxide and

  • A. propane
  • B. butane
  • C. methaneCorrect
  • D. ethane

Explanation

The decarboxylation of ethanoic acid produces carbon(IV) oxide and methane: CH3COOH → CH4 + CO2.

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