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JAMB Chemistry 2013 Objective — Question 5

Question 5 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2013 Objective paper, with the correct answer and a full explanation.

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The rate of diffusion of a gas Y is twice that of Z. If the relative molecular mass of Y is 64 and the two gases diffuse under the same conditions, find the relative molecular mass of Z.

  • A. 8
  • B. 16
  • C. 32
  • D. 4

Explanation

Using Graham's law: R₁/R₂ = √(M₂/M₁). Since R(Y)=2R(Z): 2 = √(M(Z)/64), so M(Z)/64 = 4, giving M(Z) = 256. This value does not match any of the given options — the printed key states 'No Correct Option'.

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