JAMB Chemistry 2017 Objective — Question 33
Question 33 of 40 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2017 Objective paper, with the correct answer and a full explanation.
Advertisement
Calculate the amount in moles of silver deposited when 9650C of electricity is passed through a solution of silver salt (1F=96500Cmol⁻¹).
- A. A. 0.03
- B. B. 10.80
- C. C. 10.00
- D. D. 0.10Correct
Explanation
Ag⁺(aq)+e⁻→Ag(s); 1 mole Ag requires 1F (96500C). Moles deposited = 9650/96500 = 0.10 mol.
Advertisement
Sign up free to unlock
- Score tracking
- Practice history
- Saved questions
- Progress dashboard
- Personalized sessions
- Weak-topic breakdown
…and/or go further with premium services and No Ads.