JAMB Chemistry 2025 Objective — Question 10
Question 10 of 40 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2025 Objective paper, with the correct answer and a full explanation.
Advertisement
What volume of O₂ in dm³ (measured at STP) is liberated when a current of 5 A is passed through acidified water for 965 s (1F = 96500 C)?
- A. 0.28Correct
- B. 0.056
- C. 0.112
- D. 0.21
Explanation
Q = It = 5×965 = 4825 C. 4e⁻ needed per mole of O₂ (40H⁻ → 2H₂O + O₂ + 4e⁻). Moles O₂ = 4825/(4×96500). Volume = [4825/(4×96500)] × 22.4 dm³ = 0.28 dm³.
Advertisement
Sign up free to unlock
- Score tracking
- Practice history
- Saved questions
- Progress dashboard
- Personalized sessions
- Weak-topic breakdown
…and/or go further with premium services and No Ads.