JAMB Chemistry 2025 Objective — Question 6

Question 6 of 40 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2025 Objective paper, with the correct answer and a full explanation.

What volume of 0.2 mol dm⁻³ NaOH solution will be required to neutralise 20 cm³ of 0.5 M H₂SO₄?

A. 25 cm³
B. 50 cm³
C. 75 cm³
D. 100 cm³Correct

Explanation

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O. Moles H₂SO₄ = 0.5×0.02 = 0.01 mol. Moles NaOH needed = 0.02 mol. V = 0.02/0.2 = 0.1 L = 100 cm³.

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