JAMB Mathematics 2008 Objective — Question 33

Question 33 of 50 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2008 Objective paper, with the correct answer and a full explanation.

Find the gradient of a line which is perpendicular to the line with the equation 3x+2y+1=0

A. 3/2
B. 2/3Correct
C. -2/3
D. -3/2

Explanation

3x+2y+1=0. 2y=-1-3x-1. y=-3x/2-1/2. Gradient m1=-3/2. Since the new line is perpendicular to it, m2=-1/m1=2/3.

Sign up free to unlock

Score tracking
Practice history
Saved questions
Progress dashboard
Personalized sessions
Weak-topic breakdown

…and/or go further with premium services and No Ads.

Create free account

More questions from Mathematics 2008 Objective More Mathematics past papers