JAMB Mathematics 2009 Objective — Question 8

Question 8 of 50 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2009 Objective paper, with the correct answer and a full explanation.

If log(base 10) 2 = 0.3010 and log(base 10) 7 = 0.8451, evaluate log(base 10) 280

A. 0.4471
B. 2.4471Correct
C. 1.2271
D. 1.1071

Explanation

log280 = log(4x7x10) = log4+log7+log10 = 2log2+0.8451+1 = 2(0.3010)+1.8451 = 2.4471.

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