JAMB Mathematics 2010 Objective — Question 39

Question 39 of 50 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2010 Objective paper, with the correct answer and a full explanation.

39. From triangle PQR, with angle P=60 degrees, side PQ=8cm, side PR=q, and area 12sqrt3 cm2, find q. A. 5cm B. 6cm C. 7cm D. 8cm

• A. 5cm
• B. 6cmCorrect
• C. 7cm
• D. 8cm

Explanation

Area = 1/2 q r sin P. 12sqrt3 = 1/2 x q x 8 x sin60. 24sqrt3 = 8q x (sqrt3/2). 24sqrt3/4sqrt3 = q. q = 6cm.

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