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JAMB Mathematics 2013 Objective — Question 32

Question 32 of 50 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2013 Objective paper, with the correct answer and a full explanation.

Find the equation of the perpendicular bisector of the line joining P(2,−3) to Q(−5,1).

A. A. 8y+14x+13=0
B. B. 8y−14x+13=0Correct
C. C. 8y−14x−13=0
D. D. 8y+14x−13=0

Explanation

Midpoint=(−3/2,−1); slope of PQ=−4/7; perp slope=7/4; equation: 8y−14x+13=0.

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