JAMB Mathematics 2015 Objective — Question 4

Question 4 of 50 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2015 Objective paper, with the correct answer and a full explanation.

Determine the maximum value of y = 3x² − x³.

• A. 5
• B. 4Correct
• C. 2
• D. 0

Explanation

dy/dx = 6x−3x² = 0 ⟹ x=0 or x=2. At x=2, y = 3(4)−8 = 4 (maximum).

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