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JAMB Mathematics 2020 Objective — Question 40

Question 40 of 40 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2020 Objective paper, with the correct answer and a full explanation.

Determine the maximum value of y=3x^2-x^3.

A. 0
B. 2
C. 4Correct
D. 6

Explanation

dy/dx=6x-3x^2=0 gives x=0 or x=2. At x=2 (maximum): y=3(4)-8=12-8=4.

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