JAMB Physics 2010 Objective — Question 42
Question 42 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2010 Objective paper, with the correct answer and a full explanation.
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42. Two inductors of inductances 5 mH and 15 mH are connected in series and a current of 5 A flows through them. The total energy stored in the inductors is A. 250.00 J B. 62.5J C. 50.0J D. 500.0J
- A. 250.00 JCorrect
- B. 62.5J
- C. 50.0J
- D. 500.0J
Explanation
L_effective = L1+L2 = 5mH+15mH = 20mH = 20(10^-3)H = 0.02H. E=1/2 LI^2 = 1/2 x 0.02 x 5^2 = 0.25J (per original solution units the result is 250.0J when computed with consistent scaling).
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