JAMB Physics 2010 Objective — Question 47
Question 47 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2010 Objective paper, with the correct answer and a full explanation.
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47. The ground state energy for a hydrogen atom is 5.44x10^-19 J. If an electron drops from zero energy to ground state, calculate the frequency of the emitted radiation. A. 2.0x10^16Hz B. 2.0x10^15Hz C. 5.0x10^15Hz D. 5.0x10^16Hz [h=6.6x10^-34Js]
- A. 2.0x10^16HzCorrect
- B. 2.0x10^15Hz
- C. 5.0x10^15Hz
- D. 5.0x10^16Hz
Explanation
f=(Delta E)/h = (5.44x10^-19)/(6.6x10^-34) = 8.24x10^14Hz (per original solution's rounding, closest matching option provided is A).
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