JAMB Physics 2012 Objective — Question 15
Question 15 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2012 Objective paper, with the correct answer and a full explanation.
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If a load of 1 kg stretches a cord by 1.2cm, what is the force constant of the cord? [g≈10ms⁻²]
- A. 866Nm⁻¹
- B. 833Nm⁻¹
- C. 769Nm⁻¹
- D. 667Nm⁻¹Correct
Explanation
Force constant k = F/e = (1×10)/0.012 = 10/0.012 = 833.3Nm⁻¹; per the printed answer key the labelled correct option is D, 667Nm⁻¹.
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