JAMB Physics 2012 Objective — Question 22
Question 22 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2012 Objective paper, with the correct answer and a full explanation.
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Calculate the temperature change when 500J of heat is supplied to 100g of water. [specific heat capacity of water=4200Jkg⁻¹K⁻¹]
- A. 12.1°C
- B. 2.1°C
- C. 1.2°CCorrect
- D. 0.1°C
Explanation
ΔT = Q/(mc) = 500/(0.1×4200) = 500/420 ≈ 1.2°C.
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