JAMB Physics 2013 Objective — Question 13
Question 13 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2013 Objective paper, with the correct answer and a full explanation.
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Calculate the work done when a force of 20N stretches a spring by 5mm.
- A. 0.5JCorrect
- B. 1.5J
- C. 2.0J
- D. 2.5J
Explanation
F=20N, e=5mm=0.05m. Work done = ½Fe = ½×20×0.05 = 0.5J.
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