JAMB Physics 2013 Objective — Question 36
Question 36 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2013 Objective paper, with the correct answer and a full explanation.
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Calculate the force acting on an electron of charge 1.5×10⁻¹⁹C placed in an electric field of intensity 10⁵Vm⁻¹.
- A. 1.5×10⁻¹¹N
- B. 1.5×10⁻¹²N
- C. 1.5×10⁻¹³N
- D. 1.5×10⁻¹⁴NCorrect
Explanation
F = Eq = 10⁵×1.5×10⁻¹⁹ = 1.5×10⁻¹⁴N.
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